tweaks: elide three checks of a shortcut's meta flag
A control code cannot be a Meta keystroke, and a plain printable character as key code necessarily means it is a Meta keystroke. So, comparing just the key code is enough.master
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620553b795
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196e913681
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@ -443,10 +443,7 @@ size_t shown_entries_for(int menu)
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return count;
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}
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/* Return the shortcut that corresponds to the values of kbinput (the
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* key itself) and meta_key (whether the key is a meta sequence). The
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* returned shortcut will be the first in the list that corresponds to
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* the given sequence. */
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/* Return the first shortcut in the current menu that matches the given input. */
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const keystruct *get_shortcut(int *kbinput)
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{
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/* Plain characters and upper control codes cannot be shortcuts. */
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@ -462,8 +459,7 @@ const keystruct *get_shortcut(int *kbinput)
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return NULL;
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for (keystruct *s = sclist; s != NULL; s = s->next) {
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if ((s->menus & currmenu) && *kbinput == s->keycode &&
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meta_key == s->meta)
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if ((s->menus & currmenu) && *kbinput == s->keycode)
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return s;
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}
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@ -823,8 +823,7 @@ void parse_binding(char *ptr, bool dobind)
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assign_keyinfo(newsc, keycopy, keycode);
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/* Disallow rebinding ^[ and frequent escape-sequence starter "Esc [". */
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if ((!newsc->meta && newsc->keycode == ESC_CODE) ||
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(newsc->meta && newsc->keycode == '[')) {
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if (newsc->keycode == ESC_CODE || newsc->keycode == '[') {
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jot_error(N_("Keystroke %s may not be rebound"), keycopy);
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free_things:
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free(keycopy);
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