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tweaks: improve four comments

master
Benno Schulenberg 2020-07-20 17:15:06 +02:00
parent 57c52de99a
commit a0d2e63c8e
1 changed files with 7 additions and 10 deletions
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17
src/winio.c
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@ -837,31 +837,28 @@ int parse_escape_sequence(int firstbyte)
#define PROCEED -44 #define PROCEED -44
/* Turn a three-digit decimal number (from 000 to 255) into its corresponding /* For each consecutive call, gather the given digit into a three-digit
* byte value. */ * decimal byte code (from 000 to 255). Return the assembled code when
* it is complete, but until then return PROCEED when the given digit is
* valid, and the given digit itself otherwise. */
int assemble_byte_code(int kbinput) int assemble_byte_code(int kbinput)
{ {
static int byte = 0; static int byte = 0;
/* Check that the given digit is within the allowed range for its position.
* If yes, store it. If no, return the digit (or character) itself. */
switch (++digit_count) { switch (++digit_count) {
case 1: case 1:
/* The first digit (the 100's position) is from zero to two. */ /* The first digit is either 0, 1, or 2. */
byte = (kbinput - '0') * 100; byte = (kbinput - '0') * 100;
return PROCEED; return PROCEED;
case 2: case 2:
/* The second digit (the 10's position) must be from zero to five /* The second digit may be at most 5 if the first was 2. */
* if the first was two, and may be any decimal value otherwise. */
if (byte < 200 || kbinput <= '5') { if (byte < 200 || kbinput <= '5') {
byte += (kbinput - '0') * 10; byte += (kbinput - '0') * 10;
return PROCEED; return PROCEED;
} else } else
return kbinput; return kbinput;
case 3: case 3:
/* The third digit (the 1's position) must be from zero to five /* The third digit may be at most 5 if first two were 2 and 5. */
* if the first was two and the second was five, and may be any
* decimal value otherwise. */
if (byte < 250 || kbinput <= '5') { if (byte < 250 || kbinput <= '5') {
return (byte + kbinput - '0'); return (byte + kbinput - '0');
} else } else